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-3s^2+3s-1=-91
We move all terms to the left:
-3s^2+3s-1-(-91)=0
We add all the numbers together, and all the variables
-3s^2+3s+90=0
a = -3; b = 3; c = +90;
Δ = b2-4ac
Δ = 32-4·(-3)·90
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-33}{2*-3}=\frac{-36}{-6} =+6 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+33}{2*-3}=\frac{30}{-6} =-5 $
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